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Implement Ref::try_into_{ref,mut} #1184

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Implement Ref::try_into_{ref,mut} #1184

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jswrenn
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@jswrenn jswrenn commented May 3, 2024

Wip. Currently a borrow-checker puzzle.

@joshlf
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joshlf commented May 4, 2024

Wip. Currently a borrow-checker puzzle.

I believe this is impossible to fix w/o adding bounds. IntoByteSlice doesn't imply Copy, and so self.0.into() irrevocably moves self.0. You'd need to add a Copy bound or some way of reversing the into() operation (ie, to reconstruct the value stored in self.0 given the error).

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jswrenn commented May 4, 2024

Perhaps there's a way forward doing &*self.0 instead? We only need to call is_bit_valid, here.

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joshlf commented May 4, 2024

Unfortunately that wouldn't live long enough. It would have the lifetime of the stack frame, but we need to return from the stack frame

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jswrenn commented May 7, 2024

Unfortunately that wouldn't live long enough. It would have the lifetime of the stack frame, but we need to return from the stack frame

Would you like me to provide that hat you'll eat, or will you be providing your own? ;-)

@jswrenn jswrenn requested a review from joshlf May 7, 2024 12:13
@jswrenn jswrenn force-pushed the ref-try_into branch 2 times, most recently from 9f62f39 to fa5ec71 Compare May 7, 2024 12:29
src/lib.rs Outdated

/// Attempts to convert this `Ref<_, T>` into a `&T`.
///
/// `try_into_ref` consumes the `Ref`, and returns a reference to `T`.
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Document why this could fail?

if !is_bit_valid {
Err(ValidityError::new(self))
} else {
match Ptr::from_ref(self.0.into()).try_cast_into_no_leftover::<T>() {
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Is there any way we can keep the original Ptr and avoid calling constructing it twice?

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Not that I can find, unfortunately. It might be possible with more unsafe code.

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We might be able to do something like this, but lifetime extension makes me nervous:

    /// Attempts to convert this `Ref<_, T>` into a `&mut T`.
    ///
    /// `try_into_mut` consumes the `Ref`, and returns a reference to `T`.
    #[must_use = "has no side effects"]
    #[inline(always)]
    pub fn try_into_mut(mut self) -> Result<&'a mut T, ValidityError<Self, T>>
    where
        T: TryFromBytes,
    {
        // Extend the lifetime of `&mut *self.0` to `'a`.
        // SAFETY: Idk, this feels sketchy.
        let bytes = unsafe { mem::transmute::<&mut [u8], &'a mut [u8]>(&mut *self.0) };
        match Ptr::from_mut(bytes).try_cast_into_no_leftover::<T>() {
            Ok(candidate) => {
                match candidate.try_into_valid() {
                    Ok(candidate) => Ok(candidate.as_mut()),
                    Err(e) => Err(e.with_src(self)),
                }
            }
            Err(CastError::Validity(i)) => match i {},
            Err(CastError::Alignment(_) | CastError::Size(_)) => {
                // SAFETY: By invariant on `Ref::0`, the referenced byte slice
                // is aligned to `T`'s alignment and its size corresponds to a
                // valid size for `T`. Since properties are checked upon
                // constructing `Ref`, these failures are unreachable.
                unsafe { core::hint::unreachable_unchecked() }
            },
        }
    }

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If IntoByteSlice documented that .into() behaved identically to .deref(), this might be fine?

src/lib.rs Outdated

/// Attempts to convert this `Ref<_, T>` into a `&mut T`.
///
/// `try_into_mut` consumes the `Ref`, and returns a reference to `T`.
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Document why this could fail?

if !is_bit_valid {
Err(ValidityError::new(self))
} else {
match Ptr::from_mut(self.0.into()).try_cast_into_no_leftover::<T>() {
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Is there any way we can keep the original Ptr and avoid calling constructing it twice?

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2 participants